PS! [This mail is edited.. No personal information is left in this text.] ----- Original Message ----- Sent: 23. februar 2002 17:56 Hello again. I would like to help you, but it seems helpless to talk you throu when your server does not seem to respond correctly. phpinfo(); is documented in the phpmanual here: http://www.php.net/manual/en/function.phpinfo.php You can try this...Find line 65 in divx.php,(looks like this: while ($v=mysql_fetch_array($query)) { Try changing it to: while ($v=mysql_fetch_array($query) or die(mysql_error())) { Then you get some more output on what the error is. Then send me the output. Rolf ----- Original Message ----- Sent: 23. februar 2002 17:18 Hello, So, I īcanīt find a funktion like phpinfo(). yes, my php supports mysql. one thing is, that i dont know what to do with the file (divx.php). It means, I donīt know how to configure it. The rights on the server Iīve set on 777 (CHMOD). N. ----- Original Message ----- Sent: 23. February 2002 16:31 Hello, Can you give me an output of the phpinfo(); ? Is your php build with mysql support. Does other mysql work correctly, have you flushed previliges, created the database and table and give the sqluser the right access? What do you do when you get this error? Rolf ----- Original Message ----- Sent: 23. February 2002 15:26 Hello, I installed your script for the divx database, but I got a error message at the connect on the web: Warning: Supplied argument is not a valid MySQL result resource in /path/to/divx.php on line 65 What does it mean and what i have to do? greetings N.